exercise/01: 4 sites conventional fcc cell for Cu
In this exercise we will use a different setups for fcc lattice.
Copy all input files from exercise/00:
Hint
make sure we are in the path exercise/
cp -r 00/* 01/
rm -f 01/*/*.{prn,log,kstr,bmdl,shape,bmdl,kgrn,kfcd,out} 01/*/*/*
Modify kstr and bmdl for conventional fcc unit cell:
Hint
NQ
andLAT
for kstr and bmdla/w
in kstr
--- /home/runner/work/emto-best-practices/emto-best-practices/content/exercise/solutions/00/kstr/fcc.dat
+++ /home/runner/work/emto-best-practices/emto-best-practices/content/exercise/solutions/01/kstr/fcc.dat
@@ -5,11 +5,17 @@
Slope matrices, fcc (spdf), (kappa*w)^2= 0.0
NL.....= 4 NLH...=11 NLW...= 9 NDER..= 6 ITRANS= 3 NPRN..= 0
(K*W)^2..= 0.000000 DMAX....= 1.7000 RWATS...= 0.10
-NQ3...= 1 LAT...= 2 IPRIM.= 0 NGHBP.=13 NQR2..= 0
+NQ3...= 4 LAT...= 1 IPRIM.= 0 NGHBP.=13 NQR2..= 0
A........= 1.0000000 B.......= 1.0000000 C.......= 1.0000000
-BSX......= 0.5000000 BSY.....= 0.5000000 BSZ.....= 0.0000000
-BSX......= 0.0000000 BSY.....= 0.5000000 BSZ.....= 0.5000000
-BSX......= 0.5000000 BSY.....= 0.0000000 BSZ.....= 0.5000000
+BSX......= 1.0000000 BSY.....= 0.0000000 BSZ.....= 0.0000000
+BSX......= 0.0000000 BSY.....= 1.0000000 BSZ.....= 0.0000000
+BSX......= 0.0000000 BSY.....= 0.0000000 BSZ.....= 1.0000000
QX(IQ)...= 0.0000000 QY......= 0.0000000 QZ......= 0.0000000
+QX(IQ)...= 0.5000000 QY......= 0.5000000 QZ......= 0.0000000
+QX(IQ)...= 0.5000000 QY......= 0.0000000 QZ......= 0.5000000
+QX(IQ)...= 0.0000000 QY......= 0.5000000 QZ......= 0.5000000
+a/w(IQ)..= 0.70 0.70 0.70 0.70
+a/w(IQ)..= 0.70 0.70 0.70 0.70
+a/w(IQ)..= 0.70 0.70 0.70 0.70
a/w(IQ)..= 0.70 0.70 0.70 0.70
LAMDA....= 2.5000 AMAX....= 4.5000 BMAX....= 4.5000
put 4 Cu on these 4 sites in kgrn
Hint
NT=1
and allIT
should be same: 4 Cu atoms should be equivalent.IBZ=1
for simple cubic symmetry.
--- /home/runner/work/emto-best-practices/emto-best-practices/content/exercise/solutions/00/kgrn/cu.dat
+++ /home/runner/work/emto-best-practices/emto-best-practices/content/exercise/solutions/01/kgrn/cu.dat
@@ -15,7 +15,7 @@
NITER.= 50 NLIN.= 31 NPRN.= 0 NCPA.= 7 NT...= 1 MNTA.= 1
MODE..= 3D FRC..= N DOS..= N OPS..= N AFM..= P CRT..= M
Lmaxh.= 8 Lmaxt= 4 NFI..= 31 FIXG.= 2 SHF..= 0 SOFC.= N
-KMSH...= G IBZ..= 2 NKX..= 0 NKY..= 13 NKZ..= 0 FBZ..= N
+KMSH...= G IBZ..= 1 NKX..= 0 NKY..= 13 NKZ..= 0 FBZ..= N
KMSH2..= G IBZ2.= 1 NKX2.= 4 NKY2.= 0 NKZ2.= 51
ZMSH...= C NZ1..= 16 NZ2..= 8 NZ3..= 8 NRES.= 4 NZD.=1500
DEPTH..= 1.000 IMAGZ.= 0.020 EPS...= 0.200 ELIM..= -1.000
@@ -26,6 +26,9 @@
EFGS...= 0.000 HX....= 0.100 NX...= 5 NZ0..= 6 STMP..= N
Symb IQ IT ITA NZ CONC Sm(s) S(ws) WS(wst) QTR SPLT Fix
Cu 1 1 1 29 1.000 1.000 1.000 1.000 0.0 0.0 N
+Cu 2 1 1 29 1.000 1.000 1.000 1.000 0.0 0.0 N
+Cu 3 1 1 29 1.000 1.000 1.000 1.000 0.0 0.0 N
+Cu 4 1 1 29 1.000 1.000 1.000 1.000 0.0 0.0 N
Atom: 4 lines + NT*NTA*6 lines
IEX...= 4 NP..= 251 NES..= 15 NITER=100 IWAT.= 0 NPRNA= 0
VMIX.....= 0.300000 RWAT....= 3.500000 RMAX....= 20.000000
run all of the calculations and compare the total energy in kfcd for these 2 different fcc setups.
The energy of two setups should be same/close, but if not ?
Hint
we could play with the k-points for convergence test.
e.g:
NKY=37 for 00/kgrn/cu.dat
NKY=19 for 01/kgrn/cu.dat